Different app. load value & no steps -> different results!?

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CMiculas
Posts: 26
Joined: Wed Oct 25, 2017 6:23 am
Location: University of Coimbra

Different app. load value & no steps -> different results!?

Post by CMiculas » Mon Sep 24, 2018 6:09 am

Dear all,

I am performing some research on steel frames and joints.
Using the same type of integrator (load control) with the value of 0.1 and changing the number of steps and the value of the applied force, I obtain some very different results.
Please check the results file in my dropbox: https://www.dropbox.com/s/6pl5uaayymqeq ... s.JPG?dl=0

Can anyone please suggest me why the results are not the same or why they are so different? :roll:

Definition of the analysis (red curve):
...
set p1 -250000.0;
...
# Analysis Definition
constraints Transformation;
numberer Plain;
system BandGeneral;
# test NormDispIncr 1.0e-10 3;
algorithm Linear;
integrator LoadControl 0.1;
analysis Static;
analyze 14;

Definition of the analysis (yellow curve):
...
set p1 -350000;
...
# Analysis Definition
constraints Transformation;
numberer Plain;
system BandGeneral;
# test NormDispIncr 1.0e-10 3;
algorithm Linear;
integrator LoadControl 0.1;
analysis Static;
analyze 10;

selimgunay
Posts: 913
Joined: Mon Sep 09, 2013 8:50 pm
Location: University of California, Berkeley

Re: Different app. load value & no steps -> different result

Post by selimgunay » Mon Sep 24, 2018 12:32 pm

It looks like you are applying 1.4 times larger force in the first one

CMiculas
Posts: 26
Joined: Wed Oct 25, 2017 6:23 am
Location: University of Coimbra

Re: Different app. load value & no steps -> different result

Post by CMiculas » Tue Sep 25, 2018 1:41 am

yes, but that value of the force will be equal to the one in the second case, so both cases have the same value of the force, right?
case 1 => force x load control x no steps = 250 000 * 0.1 * 14 = 350 000
case 2 => force x load control x no steps = 350 000 * 0.1 * 10 = 350 000

selimgunay
Posts: 913
Joined: Mon Sep 09, 2013 8:50 pm
Location: University of California, Berkeley

Re: Different app. load value & no steps -> different result

Post by selimgunay » Tue Sep 25, 2018 11:11 am

In the first case, you may be applying on the first 10 steps as they amount to 100% according to the value of the parameter in the load command. Second one is correct. TO check you can update the second case as

integrator LoadControl [expr 1.0/14.0];
analysis Static;
analyze 14;

Prafullamalla
Posts: 160
Joined: Mon Feb 02, 2015 6:32 pm

Re: Different app. load value & no steps -> different result

Post by Prafullamalla » Tue Sep 25, 2018 9:17 pm

I believe that the displacement should be same for both the condition. Mistake might be during calculation of force while plotting the graph for particular displacement
Prafulla Malla, Nepal
Praf_malla@hotmail.com

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