Learning Openseespy through a very simple example [one more good drift, but still failure]

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skypass
Posts: 15
Joined: Thu May 27, 2021 9:37 am

Learning Openseespy through a very simple example [one more good drift, but still failure]

Post by skypass » Thu May 27, 2021 10:59 am

Hi all,
Just new in this community, please be patient to read what I'm looking for.

According to the last release of Openseespy manual, downloadable from here

Code: Select all

https://buildmedia.readthedocs.org/media/pdf/openseespydoc/latest/openseespydoc.pdf
is quite difficult (for newcomers in this module, even being strong in python, like me) to have an immediate vision of such a package.

So, my proposal is: could someone post a .py code to solve this basic problem?

Code: Select all

  Given: 
  * a beam between two simple supports, span L= 4 m
  * charged with a distributed load w= 5 kN/m
  * having the following geo-mechanics parameters 
    E= 2e11  pascal # steel modulus of elasticity
    I=1.6e-5 m^4    # beam inertial moment
    # Neglected section area
    
  Find: 
  * elastica diagram (plot and deformation values)
    spanned 10% (or more) of length L    
Thanks in advance

EDIT: what I'm expecting from Openseespy

Code: Select all

# ---- elastica.py -------
L= 4.0 # m
w= 5.0 # kN/m
E= 2e11   # pascal
I= 1.6e-5 # m^4
#
max_displ= 5/384*w*L**4/(E*I) # Elasticity theory
print('\n Max_displacement at midspan=  {:.4e}'.format(max_displ), 'm \n')

Nsteps=17
#
print('{:>7}{:>10}'.format('x', 'eta'))
print('{:>22}'.format('------------------'))
for k in range(Nsteps):
    eta= 1.0/(E*I)*(w*(k/L)**4/24 - w*L*(k/L)**3/12 + w*L**3*(k/L)/24 )
    print ('{:>9.2f}{:>12.4e}'. format(k/L, eta) )
print('{:>22}'.format('------------------'))
# EOF: elastica.py
'''
 Max_displacement at midspan=  5.2083e-06 m

      x       eta
    ------------------
     0.00  0.0000e+00
     0.25  1.0338e-06
     0.50  2.0223e-06
     0.75  2.9259e-06
     1.00  3.7109e-06
     1.25  4.3500e-06
     1.50  4.8218e-06
     1.75  5.1109e-06
     2.00  5.2083e-06
     2.25  5.1109e-06
     2.50  4.8218e-06
     2.75  4.3500e-06
     3.00  3.7109e-06
     3.25  2.9259e-06
     3.50  2.0223e-06
     3.75  1.0338e-06
     4.00  0.0000e+00
    ------------------
'''

Last edited by skypass on Sun Jun 06, 2021 8:28 am, edited 6 times in total.

mhscott
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Joined: Tue Jul 06, 2004 3:38 pm
Location: Corvallis, Oregon USA
Contact:

Re: Learning Openseespy through a very simple example

Post by mhscott » Fri May 28, 2021 11:14 am

This is close to what you're looking for: https://portwooddigital.com/2020/11/03/ ... oad-beams/

skypass
Posts: 15
Joined: Thu May 27, 2021 9:37 am

Re: Learning Openseespy through a very simple example

Post by skypass » Fri May 28, 2021 9:01 pm

Oh yes! Thank you, the test below, applied to your suggested code, gives fine results, being known that warning tags need to be deeply investigated.
One more question, please. Which is the command for defining a load uniformly distributed on a beam?
Cheers
EDIT: Just found the answer for distributed load, similar to:

Code: Select all

Wy = -10.e+3
Wx = 0.
Ew = {3: ['-beamUniform', Wy, Wx]}

Code: Select all

C:\Training>python mycode.py
WARNING analysis Static - no Algorithm yet specified,
 NewtonRaphson default will be used
WARNING analysis Static - no ConstraintHandler yet specified,
 PlainHandler default will be used
WARNING analysis Static - no Numberer specified,
 RCM default will be used
WARNING analysis Static - no Integrator specified,
 StaticIntegrator default will be used
WARNING analysis Static - no LinearSOE specified,
 ProfileSPDLinSOE default will be used
 
Node 1 reaction=12.5, expected=12.5
Node 2 reaction=-12.5, expected=-12.5
Node 1 rotation=-0.0029556650246305416, expected=-0.002955665024630542
Node 2 rotation=0.005911330049261084, expected=0.005911330049261084

skypass
Posts: 15
Joined: Thu May 27, 2021 9:37 am

Re: Learning Openseespy through a very simple example

Post by skypass » Sat May 29, 2021 9:05 am

Could someone tell my how to obtain values of displacements, in order to compare with the ones of first post?
Here is the code I've used. Thanks in advance.
Plotted displacements: Image

Code: Select all

# --- s.py ---  May.29, 2021 ----
# simply supported beam with distributed load on 
#
import openseespy.opensees as ops
import openseespy.postprocessing.ops_vis as opsv

import matplotlib.pyplot as plt

ops.wipe()
ops.model('basic', '-ndm', 2, '-ndf', 3)

L = 4.
A = 2.e-3 
I = 1.6e-5

E = 200.e9

Ep = {1: [E, A, I]}

ops.node(1, 0., 0.)
ops.node(2,  L, 0.)

ops.fix(1, 1, 1, 0)  # node 1 soil support
ops.fix(2, 1, 1, 0)  # node 2 soil support


ops.geomTransf('Linear', 1)


ops.element('elasticBeamColumn', 1, 1, 2, A, E, I, 1) 
Wy = -5.e+3 # vertical distributed load
Wx = 0.     # horizontal distributed load

Ew = {1: ['-beamUniform', Wy, Wx]}

ops.timeSeries('Constant', 1)
ops.pattern('Plain', 1, 1)

for etag in Ew:
    ops.eleLoad('-ele', etag, '-type', Ew[etag][0], Ew[etag][1],
                Ew[etag][2])

ops.constraints('Transformation')
ops.numberer('RCM')
ops.system('BandGeneral')
ops.test('NormDispIncr', 1.0e-6, 6, 2)
ops.algorithm('Linear')
ops.integrator('LoadControl', 1)
ops.analysis('Static')
ops.analyze(1)

ops.printModel()


szer, wys = 16., 10.

fig = plt.figure(figsize=(szer/2.54, wys/2.54))
fig.subplots_adjust(left=.08, bottom=.08, right=.985, top=.94)
ax1 = plt.subplot(111)

opsv.plot_model()


sfac = opsv.plot_defo(120) # factor 120, ok

opsv.plot_defo(sfac, fmt_interp='b.-')
opsv.plot_defo(sfac, 5, interpFlag=0, fmt_nodes='bo-')
opsv.plot_defo(sfac, 3, endDispFlag=0, fmt_interp='r.--')
opsv.plot_defo(sfac, 2, fmt_interp='g.-')

sfacN, sfacV, sfacM = 5.e-5, 5.e-5, 5.e-5

plt.show()

exit()
# EOF: s.py



anuragiitg
Posts: 12
Joined: Mon Aug 26, 2013 7:52 pm
Location: The University of Utah
Contact:

Re: Learning Openseespy through a very simple example

Post by anuragiitg » Mon May 31, 2021 5:19 am

In order to get displacements at all the intermediate points, you need to divide the beam into multiple elements. Use "DiscretizeMember" from openseespy.preprocessing module.
--
Anurag Upadhyay

skypass
Posts: 15
Joined: Thu May 27, 2021 9:37 am

Re: Learning Openseespy through a very simple example

Post by skypass » Mon May 31, 2021 9:14 pm

I'll try. Thank you

skypass
Posts: 15
Joined: Thu May 27, 2021 9:37 am

Re: Learning Openseespy through a very simple example

Post by skypass » Tue Jun 01, 2021 12:45 am

Around row 70 of s2.py code shown underneath, I summarized the parameters to be filled in (taken from the guide), but
something went wrong, due to lack of experience. At end of the code is visible the error prompt.
Please, could somebody be so kind to write the appropriate parameters inside the command opsdm.DiscretizeMember()?
Thanks.

Code: Select all

# --- s2.py ---  Jun.01, 2021 ----
# simply supported beam with distributed load on 
# discretizing beam (tentative)
#
import openseespy.opensees as ops
import openseespy.postprocessing.ops_vis as opsv
import openseespy.preprocessing.DiscretizeMember as opsdm

import matplotlib.pyplot as plt

ops.wipe()
ops.model('basic', '-ndm', 2, '-ndf', 3)

L = 4.
A = 2.e-3 
I = 1.6e-5

E = 200.e9

Ep = {1: [E, A, I]}

ops.node(1, 0., 0.)
ops.node(2,  L, 0.)

ops.fix(1, 1, 1, 0)  # node 1 soil support
ops.fix(2, 1, 1, 0)  # node 2 soil support


ops.geomTransf('Linear', 1)


ops.element('elasticBeamColumn', 1, 1, 2, A, E, I, 1) 
Wy = -5.e+3 # vertical distributed load
Wx = 0.     # horizontal distributed load

Ew = {1: ['-beamUniform', Wy, Wx]}

ops.timeSeries('Constant', 1)
ops.pattern('Plain', 1, 1)

for etag in Ew:
    ops.eleLoad('-ele', etag, '-type', Ew[etag][0], Ew[etag][1],
                Ew[etag][2])

ops.constraints('Transformation')
ops.numberer('RCM')
ops.system('BandGeneral')
ops.test('NormDispIncr', 1.0e-6, 6, 2)
ops.algorithm('Linear')
ops.integrator('LoadControl', 1)
ops.analysis('Static')
ops.analyze(1)

ops.printModel()


szer, wys = 16., 10.

fig = plt.figure(figsize=(szer/2.54, wys/2.54))
fig.subplots_adjust(left=.08, bottom=.08, right=.985, top=.94)
ax1 = plt.subplot(111)

opsv.plot_model()
# ----------
opsdm.DiscretizeMember(1, 2, 1, 'elasticBeamColumn', 1, 1, 1, 1)

'''
Discretize beam elements between two nodes.

ndI (int)	node tag at I end
ndJ (int)	node tag at J end
numEle (int)	number of element to discretize
eleType (str)	the element type
integrTag (int)	beam integration tag (beamIntegration commands)
transfTag (int)	geometric transformation tag (geomTransf commands)
nodeTag (int)	starting node tag
eleTag (int)	starting element tag
'''

# ----------

sfac = opsv.plot_defo(120) # factor 120, ok

opsv.plot_defo(sfac, fmt_interp='b.-')
opsv.plot_defo(sfac, 5, interpFlag=0, fmt_nodes='bo-')
opsv.plot_defo(sfac, 3, endDispFlag=0, fmt_interp='r.--')
opsv.plot_defo(sfac, 2, fmt_interp='g.-')

sfacN, sfacV, sfacM = 5.e-5, 5.e-5, 5.e-5

plt.show()

exit()

# EOF: s2.py
'''
Compiling Errors
----------------
SectionForceDeformation *getSectionForceDeformation(int tag) - none found with tag: 1
section not found
Traceback (most recent call last):
  File "s2.py", line 65, in <module>
    opsdm.DiscretizeMember(1, 2, 1, 'elasticBeamColumn', 1, 1, 1, 1)
  File "C:\Users\Alfabeta\AppData\Local\Programs\Python\Python38\lib\site-packages\openseespy\preprocessing\Discret
izeMember.py", line 9, in DiscretizeMember
    ops.element(eleType,eleTag,ndI,ndJ,transfTag,integrTag)
opensees.OpenSeesError: See stderr output

'''

anuragiitg
Posts: 12
Joined: Mon Aug 26, 2013 7:52 pm
Location: The University of Utah
Contact:

Re: Learning Openseespy through a very simple example [beam discretization still unsolved]

Post by anuragiitg » Thu Jun 03, 2021 12:54 pm

Have you defined all the parameters needed for the "DiscretizeMember" command? It looks like you haven't defined "Integration Tag" for the element. Also, this command may not work for the "elasticBeamColumn" element. You should use the "forceBeamColumn" or "dispBeamColumn" element with an Elastic section definition.

## Define elastic section using: https://openseespydoc.readthedocs.io/en ... ction.html

section('Elastic', secTag, E_mod, A, Iz, G_mod=None, alphaY=None)

## Then define the elements using the "DiscretizeMember" command. For example, you want to define 10 small equal length elements between node 1 and node 2, with element tag starting with 1.

i_node = 1
j_node = 2
numEle = 10
eleType = "forceBeamColumn"
intTag = 1 (Define it previously. Read the manual and examples to understand what it is.)
transfTag = 1
startNodeTag = 1 (Generally same as i_node)
startEleTag =1

opsdm.DiscretizeMember(i_node, j_node, numEle, eleType, intTag, transfTag, startNodeTag, startEleTag)

## The above command will create all the elements you want between nodes 1 and 2. There is no need to define element 1 separately as you did in your script.
--
Anurag Upadhyay

anuragiitg
Posts: 12
Joined: Mon Aug 26, 2013 7:52 pm
Location: The University of Utah
Contact:

Re: Learning Openseespy through a very simple example [beam discretization still unsolved]

Post by anuragiitg » Thu Jun 03, 2021 1:23 pm

This is a great explanation by Dr. Scott.

https://portwooddigital.com/2021/06/02/ ... bers-only/
--
Anurag Upadhyay

skypass
Posts: 15
Joined: Thu May 27, 2021 9:37 am

Re: Learning Openseespy through a very simple example [good drift for beam discretization]

Post by skypass » Fri Jun 04, 2021 1:10 am

Despite the given instructions have been correctly applied (see next screenshot), errors still arise.
New code .py is uploaded below. Thx&Cheers

Code: Select all

  File "s3.py", line 65, in <module>
    opsdm.DiscretizeMember(1, 2, 10, 'forceBeamColumn', 5, 1, 1, 1)
  File "C:\Users\Alfabeta\AppData\Local\Programs\Python\Python38\lib\site-packages\openseespy\preprocessing\Discret
izeMember.py", line 37, in DiscretizeMember
    ops.node(nodeTag,Xi+i*dX,Yi+i*dY)
opensees.OpenSeesError: See stderr output
Image

File s3.py

Code: Select all

# --- s3.py ---  Jun.04, 2021 ----
# simply supported beam with distributed load on 
# discretizing beam (2^nd tentative, after forum drift)
#
import openseespy.opensees as ops
import openseespy.postprocessing.ops_vis as opsv
import openseespy.preprocessing.DiscretizeMember as opsdm

import matplotlib.pyplot as plt

ops.wipe()
ops.model('basic', '-ndm', 2, '-ndf', 3)

L = 4.
A = 2.e-3 
I = 1.6e-5

E = 200.e9

Ep = {1: [E, A, I]}

ops.node(1, 0., 0.)
ops.node(2,  L, 0.)

ops.fix(1, 1, 1, 0)  # node 1 soil support
ops.fix(2, 1, 1, 0)  # node 2 soil support


ops.geomTransf('Linear', 1)


ops.element('elasticBeamColumn', 1, 1, 2, A, E, I, 1) 
Wy = -5.e+3 # vertical distributed load
Wx = 0.     # horizontal distributed load

Ew = {1: ['-beamUniform', Wy, Wx]}

ops.timeSeries('Constant', 1)
ops.pattern('Plain', 1, 1)

for etag in Ew:
    ops.eleLoad('-ele', etag, '-type', Ew[etag][0], Ew[etag][1],
                Ew[etag][2])

#ops.constraints('Transformation')
ops.numberer('RCM')
ops.system('BandGeneral')
ops.test('NormDispIncr', 1.0e-6, 6, 2)
#ops.algorithm('Linear')
#ops.integrator('LoadControl', 1)
ops.analysis('Static')
ops.analyze(1)

ops.printModel()


szer, wys = 16., 10.

fig = plt.figure(figsize=(szer/2.54, wys/2.54))
fig.subplots_adjust(left=.08, bottom=.08, right=.985, top=.94)
ax1 = plt.subplot(111)

opsv.plot_model()
# ----------
opsdm.DiscretizeMember(1, 2, 10, 'forceBeamColumn', 5, 1, 1, 1)

'''
Parameters of DiscretizeMember() selected as follows:
----------------------------------------------------
i_node = 1
j_node = 2
numEle = 10
eleType = "forceBeamColumn"
IntTag = 5 (trapezoidal)
TransfTag= 1 (linear)
startNodeTag = 1 
startEleTag =1
'''

sfac = opsv.plot_defo(120) # factor 120, ok

opsv.plot_defo(sfac, fmt_interp='b.-')
opsv.plot_defo(sfac, 5, interpFlag=0, fmt_nodes='bo-')
opsv.plot_defo(sfac, 3, endDispFlag=0, fmt_interp='r.--')
opsv.plot_defo(sfac, 2, fmt_interp='g.-')

sfacN, sfacV, sfacM = 5.e-5, 5.e-5, 5.e-5

plt.show()

exit()

# EOF: s3.py
'''
C:\Training>python s3.py
Current Domain Information
        Current Time: 1
tCommitted Time: 1
NODE DATA: NumNodes: 2

numComponents: 2
 Node: 1
        Coordinates  : 0 0
        Disps: 0 0 -0.00416667
         unbalanced Load: 0 0 0
        ID : -1 -1 1


 Node: 2
        Coordinates  : 4 0
        Disps: 0 0 0.00416667
         unbalanced Load: 0 0 0
        ID : -1 -1 0

ELEMENT DATA: NumEle: 1

numComponents: 1
ElasticBeam2d: 1
        Connected Nodes: 1 2
        CoordTransf: 1
        mass density:  0, cMass: 0
        release code:  0
        End 1 Forces (P V M): 0 10000 0
        End 2 Forces (P V M): 0 10000 0

SP_Constraints: numConstraints: 4

numComponents: 4SP_Constraint: 0         Node: 1 DOF: 1 ref value: 0 current value: 0
SP_Constraint: 1         Node: 1 DOF: 2 ref value: 0 current value: 0
SP_Constraint: 2         Node: 2 DOF: 1 ref value: 0 current value: 0
SP_Constraint: 3         Node: 2 DOF: 2 ref value: 0 current value: 0

Pressure_Constraints: numConstraints: 0

numComponents: 0
MP_Constraints: numConstraints: 0

numComponents: 0
LOAD PATTERNS: numPatterns: 1


numComponents: 1Load Pattern: 1
  Scale Factor: 1
Constant Series: factor: 1
  Nodal Loads:

numComponents: 0
  Elemental Loads:

numComponents: 1Beam2dUniformLoad - tag 0
  Transverse: -5000
  Axial:      0
  Element acted on: 1

  Single Point Constraints:

numComponents: 0
PARAMETERS: numParameters: 0


numComponents: 0Domain::addNode - node with tag 1already exists in model
WARNING: failed to add node to domain
Traceback (most recent call last):
  File "s3.py", line 65, in <module>
    opsdm.DiscretizeMember(1, 2, 10, 'forceBeamColumn', 5, 1, 1, 1)
  File "C:\Users\Alfabeta\AppData\Local\Programs\Python\Python38\lib\site-packages\openseespy\preprocessing\Discret
izeMember.py", line 37, in DiscretizeMember
    ops.node(nodeTag,Xi+i*dX,Yi+i*dY)
opensees.OpenSeesError: See stderr output
'''

anuragiitg
Posts: 12
Joined: Mon Aug 26, 2013 7:52 pm
Location: The University of Utah
Contact:

Re: Learning Openseespy through a very simple example [good drift for beam discretization, code still fails]

Post by anuragiitg » Sun Jun 06, 2021 4:27 am

Here is a minimum working script for you,

Code: Select all

import openseespy.opensees as ops
import openseespy.preprocessing.DiscretizeMember as opsdm

import matplotlib.pyplot as plt

ops.wipe()
ops.model('basic', '-ndm', 2, '-ndf', 3)

L = 4.
A = 2.e-3 
I = 1.6e-5

E = 200.e9

Ep = {1: [E, A, I]}

ops.node(1, 0., 0.)
ops.node(2,  L, 0.)

ops.fix(1, 1, 1, 0)  # node 1 soil support
ops.fix(2, 1, 1, 0)  # node 2 soil support


ops.geomTransf('Linear', 1)

SecTag = 1
IntTag = 1

ops.section('Elastic', SecTag, E, A, I)
ops.beamIntegration('Lobatto', IntTag, SecTag, 4)

#ops.element('elasticBeamColumn', 1, 1, 2, A, E, I, 1) 

opsdm.DiscretizeMember(1, 2, 10, 'forceBeamColumn', IntTag, 1, 3, 1)

'''
Parameters of DiscretizeMember() selected as follows:
----------------------------------------------------
i_node = 1
j_node = 2
numEle = 10
eleType = "forceBeamColumn"
IntTag = 5 (trapezoidal)
TransfTag= 1 (linear)
startNodeTag = 1 
startEleTag =1
'''


Wy = -5.e+3 # vertical distributed load
Wx = 0.     # horizontal distributed load

Ew = {1: ['-beamUniform', Wy, Wx]}

ops.timeSeries('Constant', 1)
ops.pattern('Plain', 1, 1)

for etag in Ew:
    ops.eleLoad('-ele', etag, '-type', Ew[etag][0], Ew[etag][1],
                Ew[etag][2])

    
--
Anurag Upadhyay

skypass
Posts: 15
Joined: Thu May 27, 2021 9:37 am

Re: Learning Openseespy through a very simple example [good drift for beam discretization, code still fails]

Post by skypass » Sun Jun 06, 2021 8:26 am

Thanks so much, anuragiitg. Again something doesn't go properly, according to the following screenshot and the code s5.py below, derived from your drift. Prompt on opening post title: "one more good drift, but still failure"

Image

file s5.py

Code: Select all

# --- s5.py --- Jun.06. 2021
import openseespy.opensees as ops
import openseespy.preprocessing.DiscretizeMember as opsdm
import openseespy.postprocessing.ops_vis as opsv

import matplotlib.pyplot as plt

ops.wipe()
ops.model('basic', '-ndm', 2, '-ndf', 3)

L = 4.
A = 2.e-3 
I = 1.6e-5

E = 200.e9

Ep = {1: [E, A, I]}

ops.node(1, 0., 0.)
ops.node(2,  L, 0.)

ops.fix(1, 1, 1, 0)  # node 1 soil support
ops.fix(2, 1, 1, 0)  # node 2 soil support


ops.geomTransf('Linear', 1)

SecTag = 1
IntTag = 1

ops.section('Elastic', SecTag, E, A, I)
ops.beamIntegration('Lobatto', IntTag, SecTag, 4)

#ops.element('elasticBeamColumn', 1, 1, 2, A, E, I, 1) 

opsdm.DiscretizeMember(1, 2, 10, 'forceBeamColumn', IntTag, 1, 3, 1)


Wy = -5.e+3 # vertical distributed load
Wx = 0.     # horizontal distributed load

Ew = {1: ['-beamUniform', Wy, Wx]}

ops.timeSeries('Constant', 1)
ops.pattern('Plain', 1, 1)

for etag in Ew:
    ops.eleLoad('-ele', etag, '-type', Ew[etag][0], Ew[etag][1],
                Ew[etag][2])

# ---- Piece of code added to the above suggestion -------
# ---- Of course,  added ahead: import openseespy.postprocessing.ops_vis as opsv
ops.constraints('Transformation')
ops.numberer('RCM')
ops.system('BandGeneral')
ops.test('NormDispIncr', 1.0e-6, 6, 2)
ops.algorithm('Linear')
ops.integrator('LoadControl', 1)
ops.analysis('Static')
ops.analyze(1)

ops.printModel()

# plot model with tag lebels

szer, wys = 16., 10.

fig = plt.figure(figsize=(szer/2.54, wys/2.54))
fig.subplots_adjust(left=.08, bottom=.08, right=.985, top=.94)
ax1 = plt.subplot(111)

opsv.plot_model()
sfacN, sfacV, sfacM = 5.e-1, 5.e-1, 5.e-1 # scale factors
                                         

# plot deformed model
plt.figure()
# plot_defo with optional arguments
sfac = opsv.plot_defo() # 
print(f'sfac: {sfac}')  # return sfac if automatically calculated

opsv.plot_defo(sfac, fmt_interp='b.-')
opsv.plot_defo(sfac, 5, interpFlag=0, fmt_nodes='bo-')
opsv.plot_defo(sfac, 3, endDispFlag=0, fmt_interp='r.--')
opsv.plot_defo(sfac, 2, fmt_interp='g.-')

# ----------
plt.show()
# ----------

exit()
# EOF: s5.py    
'''
numComponents: 11
 Node: 1
        Coordinates  : 0 0
        Disps: 0 0 -0.000150417

 Node: 3
        Coordinates  : 0.4 0
        Disps: 0 -5.55e-05 -0.000119583

 Node: 4
        Coordinates  : 0.8 0
        Disps: 0 -9.46667e-05 -7.70833e-05

 Node: 5
        Coordinates  : 1.2 0
        Disps: 0 -0.000117833 -3.95833e-05
 
 Node: 6
        Coordinates  : 1.6 0
        Disps: 0 -0.000127 -7.08333e-06

 Node: 7
        Coordinates  : 2 0
        Disps: 0 -0.000124167 2.04167e-05

 Node: 8
        Coordinates  : 2.4 0
        Disps: 0 -0.000111333 4.29167e-05

 Node: 9
        Coordinates  : 2.8 0
        Disps: 0 -9.05e-05 6.04167e-05

 Node: 10
        Coordinates  : 3.2 0
        Disps: 0 -6.36667e-05 7.29167e-05
         unbalanced Load: 0 0 0
        ID : 4 5 6


 Node: 11
        Coordinates  : 3.6 0
        Disps: 0 -3.28333e-05 8.04167e-05

 Node: 2
        Coordinates  : 4 0
        Disps: 0 0 8.29167e-05
         unbalanced Load: 0 0 0
        ID : -1 -1 0        

ELEMENT DATA: NumEle: 10
'''

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